If y = log (sin x), prove that: cos x cose3 x.
Basic idea:
√Second order derivative is nothing but derivative of derivative i.e.
√The idea of chain rule of differentiation: If f is any real-valued function which is the composition of two functions u and v, i.e. f = v(u(x)). For the sake of simplicity just assume t = u(x)
Then f = v(t). By chain rule, we can write the derivative of f w.r.t to x as:
√Product rule of differentiation-
√Apart from these remember the derivatives of some important functions like exponential, logarithmic, trigonometric etc..
Let’s solve now:
As we have to prove: cos x cose3 x
We notice a third order derivative in the expression to be proved so first take the step to find the third order derivative.
Given, y = log (sin x)
Let’s find –
As
So lets first find dy/dx and differentiate it again.
∴
differentiating using the chain rule,
let, t = sin x and y = log t
∵ [using chain rule]
[∵ =
&
]
Differentiating again with respect to x :
[ ∵ ]
Differentiating again with respect to x:
using the chain rule and
[ ∵ cot x = cos x/sin x]