If y=e2x(ax + b), show that y2–4y1+4y = 0.

Note: y2 represents second order derivative i.e. and y1 = dy/dx


Given,


y = e2x(ax + b) ……equation 1


to prove: y2–4y1+4y = 0


We notice a second order derivative in the expression to be proved so first take the step to find the second order derivative.


Let’s find


As,


So, lets first find dy/dx


y = e2x(ax + b)


Using product rule to find dy/dx:




……..equation 2


Again differentiating w.r.t x using product rule:



…….equation 3


In order to prove the expression try to get the required form:


Subtracting 4*equation 2 from equation 3:





Using equation 1:



y2–4y1+4y = 0 ……..proved


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