Given: the side of a square is increasing at the rate of 0.2 cm/sec.

To find rate of increase of the perimeter of the square

Let the edge of the given cube be x cm at any instant time.

Then according to the given criteria,

Rate of side of the square increasing is,

Then the perimeter of the square at any time t will be

P = 4x cm.

Applying derivative with respect to time on both sides we get,

[from equation(i)]

Hence the rate of increase of the perimeter of the square will be 0.8cm/sec