A balloon in the form of a right circular cone surmounted by a hemisphere, having a diameter equal to the height of the cone, is being inflated. How fast is its volume changing with respect to its total height h, when h = 9 cm.
Given: a balloon in the form of a right circular cone surmounted by a hemisphere, having a diameter equal to the height of the cone, is being inflated
To find: how fast is its volume changing with respect to its total height h, when h = 9 cm
Solution:

Let height of the cone be h’
And the radius of the hemisphere be r
As per the given criteria,
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Let the total height of the balloon be h
Then ![]()
…………(i)
So,
Volume of the balloon (V) = Volume of the cone + Volume of the hemisphere
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This is the volume of the balloon
Now will substitute the value of h’ from equation (i), we get
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Now differentiate the above equation with respect to h, we get

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When h = 9cm, we get
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Hence at the rate of 12
cm2 the volume changes with respect to its total height.