A balloon in the form of a right circular cone surmounted by a hemisphere, having a diameter equal to the height of the cone, is being inflated. How fast is its volume changing with respect to its total height h, when h = 9 cm.

Given: a balloon in the form of a right circular cone surmounted by a hemisphere, having a diameter equal to the height of the cone, is being inflated


To find: how fast is its volume changing with respect to its total height h, when h = 9 cm


Solution:



Let height of the cone be h’


And the radius of the hemisphere be r


As per the given criteria,



Let the total height of the balloon be h


Then


…………(i)


So,


Volume of the balloon (V) = Volume of the cone + Volume of the hemisphere






This is the volume of the balloon


Now will substitute the value of h’ from equation (i), we get




Now differentiate the above equation with respect to h, we get





When h = 9cm, we get





Hence at the rate of 12 cm2 the volume changes with respect to its total height.


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