Let ‘o’ be a binary operation on the set Q0 if all non - zero rational numbers defined by a o b = ab/2, for all a, b Q0.

i. Show that ‘o’ is both commutative and associate.


ii. Find the identity element in Q0.


iii. Find the invertible elements of Q0.

We are given with the set Q0 which is the set of non - zero rational numbers.


A general binary operation is nothing but association of any pair of elements a, b from an arbitrary set X to another element of X. This gives rise to a general definition as follows:


i. A binary operation * on a set is a function*:


Here the function o:


For the ‘o’ to be commutative, aob = boa must be true for all a, b Q0. Let’s check.



a * b = b * a (as shown by 1 and 2)


Hence ‘o’ is commutative on Q0


For the ‘o’ to be associative, ao(boc) = (aob)oc must hold for every a, b, c Q0.







Hence ‘o’ is associative on Q0


ii. Identity Element: Given a binary operation*: A X A A, an element e A, if it exists, is called an identity of the operation*, if a*e = a = e*a a A.


Let e be the identity element of Q0.


Therefore, aoe = a (a Q_0)








iii. Given a binary operation with the identity element e in A, an element a A is said to be invertible with respect to the operation, if there exists an element b in A such that a * b = e = b * a and b is called the inverse of a and is denoted by a–1.


Let us proceed with the solution.


Let b Q0 be the invertible elements in Q0 of a, where a Q0.


a * b = e (We know the identity element from previous)






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