Prove that f(x) = ax + b, where a, b are constants and a > 0 is an increasing function on R.

we have,

f(x) = ax + b, a > 0


let x1,x2 R and x1 > x2


ax1 > ax2 for some a > 0


ax1 + b> ax2 + b for some b


f(x1) > f(x2)


Hence, x1 > x2 f(x1) > f(x2)


So, f(x) is increasing function of R


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