Prove that f(x) = ax + b, where a, b are constants and a > 0 is an increasing function on R.
we have,
f(x) = ax + b, a > 0
let x1,x2 R and x1 > x2
⇒ ax1 > ax2 for some a > 0
⇒ ax1 + b> ax2 + b for some b
⇒ f(x1) > f(x2)
Hence, x1 > x2⇒ f(x1) > f(x2)
So, f(x) is increasing function of R