##### Find the intervals in which the following functions are increasing or decreasing.f(x) = x3 – 6x2 + 9x + 15

Given:- Function f(x) = x3 – 6x2 + 9x + 15

Theorem:- Let f be a differentiable real function defined on an open interval (a,b).

(i) If f’(x) > 0 for all , then f(x) is increasing on (a, b)

(ii) If f’(x) < 0 for all , then f(x) is decreasing on (a, b)

Algorithm:-

(i) Obtain the function and put it equal to f(x)

(ii) Find f’(x)

(iii) Put f’(x) > 0 and solve this inequation.

For the value of x obtained in (ii) f(x) is increasing and for remaining points in its domain it is decreasing.

Here we have,

f(x) = x3 – 6x2 + 9x + 15 f’(x) = 3x2 – 12x + 9

For f(x) lets find critical point, we must have

f’(x) = 0

3x2 – 12x + 9 = 0

3(x2 – 4x + 3) = 0

3(x2 – 3x – x + 3) = 0

x2 – 3x – x + 3 = 0

(x – 3)(x – 1) = 0

x = 1, 3

clearly, f’(x) > 0 if x < 1 and x > 3

and f’(x) < 0 if 1 < x < 3

Thus, f(x) increases on (–, 1) (3, ∞)

and f(x) is decreasing on interval x (1, 3)

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