we have,

f(x) = (x + 2)e^–x

f'(x) = e^–x – e^–x (x+2)

= e^–x (1 – x – 2)

= – e^–x (x+1)

Critical points

f'(x) = 0

⇒ – e^–x (x + 1) = 0

⇒x = – 1

Clearly

Hence f(x) increases in (–∞,–1), decreases in (–1, ∞)