Show that the Lagrange's mean value theorem is not applicable to the function f(x) = 1/x on [–1, 1].

Lagrange’s mean value theorem states that if a function f(x) is continuous on a closed interval [a, b] and differentiable on the open interval (a, b), then there is at least one point x=c on this interval, such that


f(b)−f(a)=f′(c)(b−a)



This theorem is also known as First Mean Value Theorem.



Here,



f(x) exists for all values of x except 0


f(x) is discontinuous at x=0


f(x) is not continuous in [ – 1, 1]


Hence the lagrange’s mean value theorem is not applicable to the



3