Find the The Slopes of the tangent and the normal to the following curves at the indicated points :

xy = 6 at (1, 6)

Given:


xy = 56 at (1,6)


Here we have to use the product rule for above equation.


If u and v are differentiable function, then


(UV) = U + V


(xy) = (6)


x(y) + y(x) = (5)


(Constant) = 0


x + y = 0


x = – y



The Slope of the tangent at (1,6)is



= – 6


The Slope of the tangent at (1,6) is – 6


The Slope of the normal =


The Slope of the normal =


The Slope of the normal =


The Slope of the normal =


1