Find the The Slopes of the tangent and the normal to the following curves at the indicated points :
xy = 6 at (1, 6)
Given:
xy = 56 at (1,6)
Here we have to use the product rule for above equation.
If u and v are differentiable function, then
(UV) = U
+ V
(xy) =
(6)
⇒ x(y) + y
(x) =
(5)
(Constant) = 0
⇒ x + y = 0
⇒ x = – y
⇒
The Slope of the tangent at (1,6)is
⇒
⇒ = – 6
The Slope of the tangent at (1,6) is – 6
⇒ The Slope of the normal =
⇒ The Slope of the normal =
⇒ The Slope of the normal =
⇒ The Slope of the normal =