 ## Book: RD Sharma - Mathematics (Volume 2)

### Chapter: 21. Areas of Bounded Regions

#### Subject: Maths - Class 12th

##### Q. No. 27 of Exercise 21.1

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27
##### Find the area of the minor segment of the circle x2 + y2 = a2 cut off by the line .

Given equations are :

x2 + y2 = a2 ...... (1) ..... (2)

Equation (1) represents a circle with centre (0,0) and radius a, so it meets the axes at (±a,0), (0,±a).

Equation (2) represents a line parallel to y axis.

A rough sketch of the circle is given below: - We have to find the area of shaded region.

Required area

= 2(shaded region ABCA) (as the circle is symmetrical about the x - axis as well as the y - axis)

(the area can be found by taking a small slice in each region of width Δx, then the area of that sliced part will be yΔx as it is a rectangle and then integrating it to get the area of the whole region) (As x is between and the value of y varies) (as )

Substitute So the above equation becomes,  We know, So the above equation becomes,  Apply reduction formula: On integrating we get,  Undo the substituting, we get   On applying the limits we get,      Hence the area of the minor segment of the circle x2 + y2 = a2 cut off by the line is equal to square units.

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