Show that the normal to the following pairs of planes are perpendicular to each other:
i. x – y + z – 2 =0 and 3x + 2y – z +4=0
ii.
and ![]()
i. The vector equation of the plane x-y+z-2=0 can be written as
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The normal to this plane is ![]()
The vector equation of the plane 3x + 2y – z +4=0 can be written as
![]()
![]()
The normal to this plane is ![]()
Now
![]()
![]()
Hence
is perpendicular to ![]()
Therefore, the normal to the given pairs of planes are perpendicular to each other.
ii. The equation of the first plane is
![]()
The normal to this plane is ![]()
The equation of the first plane is
![]()
The normal to this plane is ![]()
Now
![]()
![]()
Hence
is perpendicular to ![]()
Therefore, the normal to the given pairs of planes are perpendicular to each other.