Show that the normal vector to the plane 2x + 2y + 2z = 3 is equally inclined with the coordinate axes.

The vector equation of the plane 2x + 2y + 2z = 3 can be written as



The normal to this plane is


Direction ratio of


Direction cosine of




Direction cosine of


So,


Let be the angle that normal makes with the coordinate axes respectively




Similarly,




Hence


So the normal vector to the plane 2x + 2y + 2z = 3 is equally inclined with the coordinate axes.


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