Show that the normal vector to the plane 2x + 2y + 2z = 3 is equally inclined with the coordinate axes.
The vector equation of the plane 2x + 2y + 2z = 3 can be written as
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The normal to this plane is ![]()
Direction ratio of ![]()
Direction cosine of ![]()
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Direction cosine of ![]()
So, ![]()
Let
be the angle that normal
makes with the coordinate axes respectively
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Similarly,
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Hence ![]()
So the normal vector to the plane 2x + 2y + 2z = 3 is equally inclined with the coordinate axes.