Find a vector of magnitude 26 units normal to the plane 12x – 3y + 4z = 1.
The vector equation of the plane 12x – 3y + 4z = 1 can be written as
The normal to this plane is
Its magnitude is
The unit vector becomes
Now a vector normal to the plane with the magnitude 26 will be
Therefore, a vector of magnitude 26 units normal to the plane 12x – 3y + 4z = 1 is