Find a vector of magnitude 26 units normal to the plane 12x – 3y + 4z = 1.

The vector equation of the plane 12x – 3y + 4z = 1 can be written as



The normal to this plane is


Its magnitude is





The unit vector becomes


Now a vector normal to the plane with the magnitude 26 will be





Therefore, a vector of magnitude 26 units normal to the plane 12x – 3y + 4z = 1 is


15