Given:

* Point : A(2, 3, –5)

* Plane : π = x + 2y – 2z – 9 = 0

We know, the distance of point (x₁,y₁,z₁) from the plane

is given by:

Putting the necessary values

⟹ Distance of the plane from A

= 3 units

∴ the distance of the point (2, 3, –5) from the plane

x + 2y – 2z – 9 = 0 is 3 units