Find the distance of the point (2, 3, 5) from the xy–plane.

Given:


* Points: A(2, 3, 5)


* Plane: z = 0


We know, the distance of point (x1,y1,z1) from the plane


is given by:



Putting the values



p = 5 units


the distance of the point (2, 3, 5) from the xy–plane is 5 units


7