As there are total of two bad eggs. Therefore while drawing 3 eggs we can draw 1 bad egg or 2 or 0 bad eggs.

Let X be the random variable denoting number of bad eggs that can be drawn in each draw.

Clearly X can take values 0,1 or 2

P(X=0) = P(all 3 are good eggs) =

[Since there are 10 good eggs so for selecting all good we took all three from 10 and 0 eggs from 2 bad ones. Total sample points are no of ways of selecting 3 eggs from total of 12 eggs]

Similarly,

P(X=1) = P(1 bad and 2 good eggs) =

P(X=2) = P(2 Bad eggs and 1 good egg) =

Now we have p_i and x_i.

Let’s proceed to find mean

Mean of any probability distribution is given by Mean = ∑x_ip_i

∴ first we need to find the products i.e. p_ix_i and add them to get mean.

Following table gives the required products :

∴ mean =