A =

|A| = 1(1 + 6) + 2(2 – 0) + 0

= 7 + 4

= 11

Now, the cofactors of A

C₁₁ = (– 1)^{1 + 1} 1 + 6 = 7

C₂₁ = (– 1)^{2 + 1} – 2 – 0 = 2

C₃₁ = (– 1)^{3 + 1} – 6 – 0 = – 6

C₁₂ = (– 1)^{1 + 2} 2 – 0 = – 2

C₂₂ = (– 1)^{2 + 1} 1 – 0 = 1

C₃₂ = (– 1)^{3 + 1} 3 – 0 = – 3

C₁₃ = (– 1)^{1 + 2} – 4 – 0 = – 4

C₂₃ = (– 1)^{2 + 1} – 2 – 0 = 2

C₃₃ = (– 1)^{3 + 1} 1 + 4 = 5

adj A =

A ^{– 1 =}

A ^{– 1} =

Now the given equation can be written as:

A X B

Or, X = A ^{– 1}B

=

X =

X =

Hence, x = 4,y = – 3 and z = 1