A =

|A| = 3(3 – 0) + 4(2 – 5) + 2(0 – 3)

= 9 – 12 – 6

= – 9

Now, the cofactors of A

C₁₁ = (– 1)^{1 + 1} 3 – 0 = 3

C₂₁ = (– 1)^{2 + 1} – 4 – 0 = 4

C₃₁ = (– 1)^{3 + 1} – 20 – 6 = – 26

C₁₂ = (– 1)^{1 + 2} 2 – 5 = 3

C₂₂ = (– 1)^{2 + 1} 3 – 2 = 1

C₃₂ = (– 1)^{3 + 1} 15 – 4 = – 11

C₁₃ = (– 1)^{1 + 2} 0 – 3 = – 3

C₂₃ = (– 1)^{2 + 1} 0 + 4 = – 4

C₃₃ = (– 1)^{3 + 1} 9 + 8 = 17

adj A =

A ^{– 1 =}

A ^{– 1} =

Now the given equation can be written as:

A X B

Or, X = A ^{– 1}B

=

X =

X =

Hence, x = 3,y = 2 and z = – 1