An amount of ₹10,000 is put into three investments at the rate of 10, 12 and 15% per annum. The combined incomes are ₹1310 and the combined income of first and second investment is ₹ 190 short of the income from the third. Find the investment in each using matrix method.
Let the numbers are x, y,z
x + y + z = 10,000 ……(i)
Also,
0.1x + 0.12y + 0.15z = 1310 …… (ii)
Again,
0.1x + 0.12y – 0.15z = – 190 …… (iii)
A X = B
|A| = 1(– 0.036) – 1(– 0.03) + 1(0)
= – 0.006
Hence, the unique solution given by x = A – 1B
C11 = – 0.036
C12 = 0.27
C13 = 0
C21 = 0.27
C22 = – 0.25
C23 = – 0.02
C31 = 0.03
C32 = – 0.05
C33 = 0.02
X = A – 1 B =
Adj A =
X =
X =
=
Hence, x = Rs 2000, y = Rs 3000 and z = Rs 5000