The function y = a log x + bx2 + x has extreme values at x = 1 and x = 2. Find a and b.

we have


y = a log x + bx2 + x



And


For maxima and minima,




Given that extreme value exist at x = 1, 2


a + 2b = – 1 ……(1)



a + 8b = – 2 …… (2)


solving (1) and (2) we get


a = – 2/3 b = – 1/6


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