Solve each of the following initial value problems

(x2 + y2)d x = 2xy dy, y(1) = 0

()dx = 2xy dy, y(1) = 0



It is a homogenous equation


Put y = vx


And


So,






Integrating both sides we get,



log (1 – ) = – log(x) + log c


log (1 – ) = log


put v =




Put y = 0,x = 1 in eq. (1),


1 – 0 = c


c = 1


put value of c in eq,(1),



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