Solve each of the following initial value problems
(x2 + y2)d x = 2xy dy, y(1) = 0
()dx = 2xy dy, y(1) = 0
It is a homogenous equation
Put y = vx
And
So,
Integrating both sides we get,
log (1 – ) = – log(x) + log c
log (1 – ) = log
put v =
Put y = 0,x = 1 in eq. (1),
1 – 0 = c
c = 1
put value of c in eq,(1),