,y(1) = 2

It is a homogeneous equation

Put y = vx

And

So,

…… (1)

2 + v = (A + B)v –A

Comparing the coefficient of like power of v,

A = – 2

A + B = 1

– 2 + B = 1

B = 3

Using in eq. (1)

– 2 log v + 3log (v – 1) = log x + c

Put the value of v,