Total number of all favorable cases is n(S) = 52

Let A be the event that first card drawn is a king. There are four kings in the pack. Hence, the probability of the first card is a king is

Let B be the event that second card is also king without replacement. Then there are 3 kings left in the pack as the cards are not replaced. Therefore, the probability of the second card is also king is

Then the probability of getting two kings without replacement is

(as there are 4 kings out of 52 cards in first draw, and 3 kings out of 51 cards in the second draw as the cards are not replaced)

The probability that both of them are kings is