A coin is tossed three times. Find P (A/B) in each of the following:

A=Heads on third toss, B=Heads on first two tosses

When a coin is tossed three times, we have following outcomes


{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}


Total outcomes =8


From above outcomes,


A= Heads on third toss = {HHH, HTH, THH, TTH} =4


Therefore probability of occurrence of event A = P(A) =


B= heads on first two tosses = {HHH, HHT} =2


Therefore probability of occurrence of event B = P(B) =


Also we want P (A B) = probability of occurrence of both events A and B


=heads on first two tosses and heads on third toss


=heads on all tosses = {HHH} = 1(Occurrence Of both A and B events


Therefore, P (A B) =


Hence, =


==(answer)


8