Mother, father and son line up at random for a family picture. If A and B are two events given by A=son on one end, B= Father in the middle, find P (A/B) and P (B/A).
Total possible outcomes =
{FMS, FSM, MFS, SMF, SFM, MSF} =6
A= Son on end = {FMS, MFS, SMF, SFM} =4
Therefore P(A) = 
B= father in middle = {MFS, SFM} = 2
Therefore P(B) = 
(A ∩ B) = son on one end and father in middle
= {MFS, SFM} =2
P(A ∩ B) = 
Hence
= 
(answer)
. 
= 
(answer)
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