Two dice are thrown. Find the probability that the numbers appeared has the sum 8, if it is known that the second die always exhibits 4.

We know total possible outcomes when two dice are thrown = 36


A= sum is 8


{(2,6),(3,5),(4,4),(5,3),(6,2)} = 5


P(A) =


B =second die exhibit 4


{(1,4),(2,4),(3,4),(4,4),(5,4),(6,4)}= 6


P(B) =


(A B) = sum of two number is 8 and also second die exhibit 4


=(4, 4) =1


P(A B) =


Therefore, = (answer)


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