We know total possible outcomes when two dice are thrown = 36

A= sum is 7

{(1,6),(2,5),(3,4),(4,3),(5,2),(6,1l} = 6

P(A) =

B =second die exhibit odd number

{(1,1),(1,3),(1,5),(2,1),(2,3),(2,5),(3,1),(3,3),(3,5),(4,1),(4,3),(4,5),(5,1),(5,3),(5,5),(6,1),(6,3),(6,5)}= 18

P(B) =

(A ∩ B) = sum of two number is 7 and also second die exhibit odd number

={(2,5),(4,3),(6,1)} =3

P(A ∩ B) =

Therefore, =

= (answer)