Given two independent events A and B such that P (A)=0.3 and P(B) = 0.6 Find
i. P (A B)
ii.
iv.
iv. P (A ∪ B)
v. P (A / B)
vi. P (B / A)
For independent event,
P(A)*P(B)=0.3*0.6=0.18
iii.
=[(1–P(A)][1–P(B)] =[1–0.3][1–0.6]
=0.7*0.4=0.28
P (A ∪ B)=P(A)+P(B)–P(A∩B)
=0.3+0.6–0.18=0.72