Find the equation of the tangent and the normal to the following curves at the indicated points:
y = x2 at (0, 0)
finding the slope of the tangent by differentiating the curve
m(tangent) at (x = 0) = 0
normal is perpendicular to tangent so, m1m2 = – 1
We can see that the slope of normal is not defined
equation of tangent is given by y – y1 = m(tangent)(x – x1)
y = 0
equation of normal is given by y – y1 = m(normal)(x – x1)
x = 0