Find the equation of the tangent and the normal to the following curves at the indicated points:

y = x2 at (0, 0)

finding the slope of the tangent by differentiating the curve



m(tangent) at (x = 0) = 0


normal is perpendicular to tangent so, m1m2 = – 1



We can see that the slope of normal is not defined


equation of tangent is given by y – y1 = m(tangent)(x – x1)


y = 0


equation of normal is given by y – y1 = m(normal)(x – x1)


x = 0


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