Find the equation of the tangent and the normal to the following curves at the indicated points:
at (2, – 2)
finding the slope of the tangent by differentiating the curve
m(tangent) at (2, – 2) = – 2
equation of tangent is given by y – y1 = m(tangent)(x – x1)
y + 2 = – 2(x – 2)
y + 2x = 2
equation of normal is given by y – y1 = m(normal)(x – x1)
2y + 4 = x – 2
2y – x + 6 = 0