Find the equation of the tangent and the normal to the following curves at the indicated points:

at (2, – 2)

finding the slope of the tangent by differentiating the curve




m(tangent) at (2, – 2) = – 2



equation of tangent is given by y – y1 = m(tangent)(x – x1)


y + 2 = – 2(x – 2)


y + 2x = 2


equation of normal is given by y – y1 = m(normal)(x – x1)



2y + 4 = x – 2


2y – x + 6 = 0


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