Find the equation of the tangent and the normal to the following curves at the indicated points:

y2 = 4a x at (a/m2, 2a/m)

finding the slope of the tangent by differentiating the curve




m(tangent) at


m(tangent) = m


normal is perpendicular to tangent so, m1m2 = – 1



equation of tangent is given by y – y1 = m(tangent)(x – x1)



equation of normal is given by y – y1 = m(normal)(x – x1)



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