Find the equation of the tangent and the normal to the following curves at the indicated points:
x2 = 4y at (2, 1)
finding the slope of the tangent by differentiating the curve
m(tangent) at (2,1) = 1
normal is perpendicular to tangent so, m1m2 = – 1
m(normal) at (2,1) = – 1
equation of tangent is given by y – y1 = m(tangent)(x – x1)
y – 1 = 1(x – 2)
equation of normal is given by y – y1 = m(normal)(x – x1)
y – 1 = – 1(x – 2)