Find the equation of the tangent and the normal to the following curves at the indicated points:

x = θ + sin θ, y = 1 + cos θ at θ = π/2.

finding slope of the tangent by differentiating x and y with respect to theta




Dividing both the above equations



m(tangent) at theta ( ) = – 1


normal is perpendicular to tangent so, m1m2 = – 1


m(normal) at theta ( ) = 1


equation of tangent is given by y – y1 = m(tangent)(x – x1)



equation of normal is given by y – y1 = m(normal)(x – x1)



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