Find the equation of the tangent and the normal to the following curves at the indicated points:
x = a sec t, y = b tan t at t.
finding slope of the tangent by differentiating x and y with respect to t
Now dividing and
to obtain the slope of tangent
m(tangent) at t =
normal is perpendicular to tangent so, m1m2 = – 1
m(normal) at t =
equation of tangent is given by y – y1 = m(tangent)(x – x1)
equation of normal is given by y – y1 = m(normal)(x – x1)