Find the equation of the normal to the curve ay2 = x3 at the point (am2, am3).
finding the slope of the tangent by differentiating the curve
m(tangent) at (am2, am3) is
normal is perpendicular to tangent so, m1m2 = – 1
m(normal) at (am2, am3) is
equation of normal is given by y – y1 = m(normal)(x – x1)