Find the equation of the tangent line to the curve y = x2 + 4x – 16 which is parallel to the line 3x – y + 1 = 0.
finding the slope of the tangent by differentiating the curve
m(tangent) = 2x + 4
equation of tangent is given by y – y1 = m(tangent)(x – x1)
now comparing the slope of a tangent with the given equation
2x + 4 = 3
Now substituting the value of x in the curve to find y
Therefore, the equation of tangent parallel to the given line is