Find the equation of the tangent line to the curve y = x2 + 4x – 16 which is parallel to the line 3x – y + 1 = 0.

finding the slope of the tangent by differentiating the curve



m(tangent) = 2x + 4


equation of tangent is given by y – y1 = m(tangent)(x – x1)


now comparing the slope of a tangent with the given equation


2x + 4 = 3



Now substituting the value of x in the curve to find y



Therefore, the equation of tangent parallel to the given line is



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