Find the binomial distribution when the sum of its mean and variance for 5 trials is 4.8.

Given that,

n = 5

Also, Mean+ Variance = 4.8

⇒np + npq = 4.8

⇒np(1+q) = 4.8

⇒5p(1+q) = 4.8

⇒5(1 - q)(1+q) = 4.8 [Since, p + q = 1]

⇒5(1 - q^{2}) = 4.8

The required binomial distribution is given by,

4