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The mean of a binomial distribution is 20, and the standard deviation 4. Calculate the parameters of the binomial distribution.
Standard deviation =
⇒ npq = 16
Therefore, np = 20, npq = 16
Let X denote the variance with parameters n and p
p + q = 1 ⇒ q = 1 - p
mean = np = 20 and variance = npq = 16
npq = 16
⇒20 q = 16
Now, np = 20
⇒ n = 100