The mean of a binomial distribution is 20, and the standard deviation 4. Calculate the parameters of the binomial distribution.

Question

Philoid · Accepted Answer

Standard deviation =

⇒ npq = 16

Therefore, np = 20, npq = 16

Let X denote the variance with parameters n and p

p + q = 1 ⇒ q = 1 - p

mean = np = 20 and variance = npq = 16

npq = 16

⇒20 q = 16

Now, np = 20

⇒ n = 100