The mean and variance of binomial variate with parameters n and p are 16 and 8 respectively. Find P (X = 0), P (X = 1) and P (X ≥ 2).

Given that parameters for binomial distribution are n, p

Now, np = 16

⇒ n = 32

The required binomial distribution is given by,

P(X≥2) = 1 - [P(X = 0) + P(X = 1)]

So,

11