Using differentials, find the approximate values of the following:
Let us assume that
Also, let x = 36 so that x + Δx = 36.6
⇒ 36 + Δx = 36.6
∴ Δx = 0.6
On differentiating f(x) with respect to x, we get
We know
When x = 36, we have
Recall that if y = f(x) and Δx is a small increment in x, then the corresponding increment in y, Δy = f(x + Δx) – f(x), is approximately given as
Here, and Δx = 0.6
⇒ Δf = (0.0833333)(0.6)
∴ Δf = 0.05
Now, we have f(36.6) = f(36) + Δf
⇒ f(36.6) = 6 + 0.05
∴ f(36.6) = 6.05
Thus,