Using differentials, find the approximate values of the following:

Let us assume that


Also, let x = 36 so that x + Δx = 36.6


36 + Δx = 36.6


Δx = 0.6


On differentiating f(x) with respect to x, we get




We know





When x = 36, we have





Recall that if y = f(x) and Δx is a small increment in x, then the corresponding increment in y, Δy = f(x + Δx) – f(x), is approximately given as



Here, and Δx = 0.6


Δf = (0.0833333)(0.6)


Δf = 0.05


Now, we have f(36.6) = f(36) + Δf



f(36.6) = 6 + 0.05


f(36.6) = 6.05


Thus,


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