Using differentials, find the approximate values of the following:

Let us assume that 
Also, let x = 36 so that x + Δx = 36.6
⇒ 36 + Δx = 36.6
∴ Δx = 0.6
On differentiating f(x) with respect to x, we get


We know



When x = 36, we have



Recall that if y = f(x) and Δx is a small increment in x, then the corresponding increment in y, Δy = f(x + Δx) – f(x), is approximately given as

Here,  and Δx = 0.6
 and Δx = 0.6
⇒ Δf = (0.0833333)(0.6)
∴ Δf = 0.05
Now, we have f(36.6) = f(36) + Δf

⇒ f(36.6) = 6 + 0.05
∴ f(36.6) = 6.05
Thus, 