We know that, in a rhombus, diagonals bisect each other at 90^o

A rough sketch of this rhombus:

(a) Draw a line segment AC of 5.2 cm and its perpendicular bisector. Let it intersect the line segment AC at point O

(b) Draw arcs of = 3.2 cm on both sides of this perpendicular bisector

Let these arcs intersect the perpendicular bisector at point B and D

(c) Join points B and D with points A and C

ABCD is the required rhombus