Find the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube
(i) 243 (ii) 256
(iii) 72 (iv) 675
(v) 100
(i) 243 = 3 x 3 x 3 x 3 x 3
Here, we can find that two 3s are left which are not forming a triplet. To make 243 a cube, one more 3 is required.
Hence,
243 x 3 = 3 x 3 x 3 x 3 x 3 x 3 = 729
729 is a perfect cube.
Therefore, the smallest natural number by which 243 should be multiplied to make it a perfect cube is 3
(ii) 256 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2
Here, we can see that two 2s are left which are not forming a triplet. To make 256 a cube, one more 2 is required
Hence,
256 x 2 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 = 512
Whereas 512 is a perfect cube.
Therefore, the smallest natural number by which 256 should be multiplied to make it a perfect cube is 2
(iii) 72 = 2 x 2 x 2 x 3 x 3
Here, we can see that two 3s are left which are not forming a triplet. In order to make 72 a cube, one more 3 is required
Hence,
72 x 3 = 2 x 2 x 2 x 3 x 3 x 3 = 216
We know that 216 is a perfect cube
Therefore, the smallest natural number by which 72 should be multiplied to make it a perfect cube is 3
(iv) 675 = 3 x 3 x 3 x 5 x 5
Here, we can see that two 5s are left which are not forming a triplet. To make 675 a cube, one more 5 is needed
Hence,
675 x 5 = 3 x 3 x 3 x 5 x 5 x 5 = 3375
We know that 3375 is a perfect cube.
Therefore, the smallest natural number by which 675 should be multiplied to make it a perfect cube is 5
(v) 100 = 2 x 2 x 5 x 5
Here, we can see that two 2s and two 5s are left which are not forming a triplet. To make 100 a cube, we require one more 2 and one more 5
Hence,
100 x 2 x 5 = 2 x 2 x 2 x 5 x 5 x 5 = 1000
We know that 1000 is a perfect cube.
Therefore, the smallest natural number by which 100 should be multiplied to make it a perfect cube is 2 x 5 = 10