In a Laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 5, 06,000.
This problem can be solved on the basis of CI problems.
Let principal (P) = 5,06,000, Rate of Interest (R) = 2.5%, Time, n = 2 hours
After 2 hours, number of bacteria, =
= 5,31,616.25
Hence, number of bacteria after two hours are 531616 (approx.)