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In a Laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 5, 06,000.

This problem can be solved on the basis of CI problems.

Let principal (P) = 5,06,000, Rate of Interest (R) = 2.5%, Time, n = 2 hours

After 2 hours, number of bacteria, =

= 5,31,616.25

Hence, number of bacteria after two hours are 531616 (approx.)

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