In a Laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 5, 06,000.
This problem can be solved on the basis of CI problems.
Let principal (P) = 5,06,000, Rate of Interest (R) = 2.5%, Time, n = 2 hours
After 2 hours, number of bacteria, =
Hence, number of bacteria after two hours are 531616 (approx.)
Calculate the amount and compound interest on
(a) Rs 10,800 for 3 years at per annum compounded annually.
(b) Rs 18,000 for years at 10% per annum compounded annually.
(c) Rs 62,500 for years at 8% per annum compounded half yearly.
(d) Rs 8,000 for 1 year at 9% per annum compounded half yearly.
(You could use the year by year calculation using SI formula to verify).
(e) Rs 10,000 for 1 year at 8% per annum compounded half yearly.