If 24x is a multiple of 3, where x is a digit, what is the value of x?

(Since 24x is a multiple of 3, its sum of digits 6 + x is a multiple of 3; so 6 + x is one of these numbers: 0, 3, 6, 9, 12, 15, 18, ... . But since x is a digit, it can only be that6 + x = 6 or 9 or 12 or 15. Therefore, x = 0 or 3 or 6 or 9. Thus, x can have any of four different values)

Since 24*x* is a multiple of 3, the sum of its digits is a multiple of 3

Sum of digits of 24*x* = 2 + 4 + *x* = 6 + *x*

Hence, 6 + *x* is a multiple of 3

This is possible when 6 + *x* is any one of these numbers 0, 3, 6, 9, and so on …

Since *x* is a single digit number, the sum of the digits can be 6 or 9 or 12 or 15 and the value of *x* comes to 0 or 3 or 6 or 9 respectively

Thus, *x* can have its value as any of the four different values 0, 3, 6, or 9

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