Book: NCERT - Mathematics

Chapter: 14. Factorisation

Subject: Maths - Class 8th

Q. No. 1 of Exercises 14.1

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Find the common factors of the given terms.(i) (ii) (iii) (iv) (v) (vi) (vii)(viii)

(i) Factor of 12 = 2× 2 × 3 ×

Factor of 36 = 2× 2 × 3× 3

Common factors are 2, 2, 3

Product of common factors = 2× 2 × 3 = 12

(ii)Factor of 2y = 2× y

Factor of 22xy = 2× 11 × x × y

Common factors are 2, y

Product of common factors = 2× y = 2y

(iii)Factor of 14pq = 2× 7 × p × q

Factor of 28p2q2= 2× 2 × 7 × p× p × q× q

Common factors are 2, 7, p, q

Product of common factors = 2× 7 × p× q = 14pq

(iv) Factor of 2x = 2 × x

Factor of 3x2= 3× x × x

Factor of 4 = 2 × 2

Common factor is 1

(v) Factor of 6abc = 2 × 3 × a × b × c

Factor of 24ab2 = 2× 2 × 2 × 3 × a × b × b

Factor of 12a2b = 2× 2 × 3 × a × a × b

Common factors are 2, 3, a, b

Product of common factors = 2× 3 × a × b = 6ab

(vi) Factor of 16x3 = 2 × 2 × 2 × 2 × x × x × x

Factor of -4x2 = -2× 2 × x × x

Factor of 32x = 2× 2 × 2 × 2 × 2 × x

Common factors are 2, 2, x

Product of common factors = 2× 2 × x = 4x

(vii) Factor of 10pq = 2 × 5 × p × q

Factor of 20qr = 2× 2 × 5 × q × r

Factor of 30rp = 2× 3 × 5 × r × p

Common factors are 2, 5

Product of common factors = 2× 5 = 10

(viii) Factor of 3x2y3 = 3 × x × x × y × y × y

Factor of 10x3y2 = 2× 5 × x × x × x × y × y

Factor of 6x2y2z = 2× 3 × x × x × y× y × z

Common factors are x × x, y × y

Product of common factors = x2y2

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