Simplify.
(i) ![]()
(ii) ![]()
(iii) ![]()
(iv) ![]()
(v) ![]()
(vi) ![]()
(vii)(m2 - n2m) 2 + 2m3n2
(viii)![]()
(i) Using Identity (a - b) 2 = a2 - 2ab + b2
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In the given expression a = ![]()
On substituting these values in the above identity, we get
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(ii) ![]()
Using Identity a2 - b2 = (a + b)(a - b)
In the given expression a = ![]()
On substituting these values in the above identity, we get
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(iii) ![]()
Using Identity (a - b)2 = a2 - 2ab + b2 for finding the value of ![]()
In the given expression a = ![]()
On substituting these values in the above identity, we get
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⇒
………………………………………………..(i)
Using Identity (a + b) 2 = a2 + 2ab + b2 for finding the value of ![]()
In the given expression a = ![]()
On substituting these values in the above identity, we get
![]()
⇒
………………………………………………..(ii)
On Adding equations (i) and (ii), we get
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(iv) ![]()
Using Identity (a + b) 2 = a2 + 2ab + b2 for finding the value of ![]()
In the given expression a = ![]()
On substituting these values in the above identity, we get
![]()
⇒
………………………………………………..(i)
Using Identity (a + b) 2 = a2 + 2ab + b2 for finding the value of ![]()
In the given expression a = ![]()
On substituting these values in the above identity, we get
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⇒
………………………………………………..(ii)
On Adding equations (i) and (ii), we get
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(v) ![]()
Using Identity (a - b) 2 = a2 - 2ab + b2 for finding the value of ![]()
In the given expression a = ![]()
On substituting these values in the above identity, we get
![]()
⇒
………………………………………………..(i)
Using Identity (a - b) 2 = a2 - 2ab + b2 for finding the value of ![]()
In the given expression a = ![]()
On substituting these values in the above identity, we get
![]()
⇒
………………………………………………..(i)
On Subtracting equations (ii) from (i), we get
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(vi) ![]()
Using Identity (a + b)2 = a2 + 2ab + b2 for finding the value of ![]()
In the given expression a = ![]()
On substituting these values in the above identity, we get
![]()
⇒
………………………………………………..(i)
On Subtracting
from (i), we get
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![]()
(vii) (m2 - n2m)2 + 2m3n2
Using Identity (a - b) 2 = a2 - 2ab + b2 for finding the value of ![]()
In the given expression a = ![]()
On substituting these values in the above identity, we get
![]()
⇒
………………………………………………..(i)
On Subtracting
from (i), we get
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(viii) ![]()
Using Identity (a - b) 2 = a2 - 2ab + b2 for finding the value of ![]()
In the given expression a = ![]()
On substituting these values in the above identity, we get
![]()
⇒
………………………………………………..(i)
On Adding
in eqn (i), we get
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First Find the value of RHS
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Using Identity (a + b) 2 = a2 + 2ab + b2 for finding the value of ![]()
In the given expression a = ![]()
On substituting these values in the above identity, we get
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⇒
………………………………………………..(ii)
Therefore from eqn (i) and equ (ii) we found that LHS = RHS