 ## Book: NCERT - Mathematics

### Chapter: 9. Algebraic Expressions and Identities

#### Subject: Maths - Class 8th

##### Q. No. 5 of Exercises 9.5

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##### Show that.(i) (ii) (iii) (iv) (v)  (i) First Find the value of LHS Using Identity (a + b) 2 = a2 + 2ab + b2 for finding the value of In the given expression a = On substituting these values in the above identity, we get  ………………………………………………..(i)

On Adding in eqn (i), we get  First Find the value of RHS Using Identity (a - b) 2 = a2 - 2ab + b2 for finding the value of In the given expression a = On substituting these values in the above identity, we get  ………………………………………………..(i)

Therefore from eqn (i) and equ (ii) we found that LHS = RHS

(ii) First Find the value of LHS Using Identity (a - b) 2 = a2 - 2ab + b2 for finding the value of In the given expression a = On substituting these values in the above identity, we get  ………………………………………………..(i)

On Adding in eqn (i), we get  First Find the value of RHS Using Identity (a + b)2 = a2 + 2ab + b2 for finding the value of In the given expression a = On substituting these values in the above identity, we get  ………………………………………………..(ii)

Therefore from eqn (i) and equ (ii) we found that LHS = RHS

(iii) First Find the value of LHS Using Identity (a - b) 2 = a2 - 2ab + b2 for finding the value of In the given expression a = On substituting these values in the above identity, we get  ………………………………………………..(i)

On Adding in eqn (i), we get  Therefore we found that LHS = RHS

(iv) First Find the value of LHS Using Identity (a + b) 2 = a2 + 2ab + b2 for finding the value of In the given expression a = On substituting these values in the above identity, we get  ………………………………………………..(i)

Using Identity (a - b) 2 = a2 - 2ab + b2 for finding the value of In the given expression a = On substituting these values in the above identity, we get  ………………………………………………..(ii)

On subtracting eqn (ii) from eqn (i), we get   Therefore we found that LHS = RHS

(v) Using Identity (a + b)(a - b) = a2 - b2

In the given expression a = On substituting these values in the above identity, we get ……………………………………………………….(i)

On substituting these values in (b - c) (b + c), we get ……………………………………………………….(ii)

On substituting these values in (c - a) (c + a), we get ……………………………………………………….(iii)

On adding eqn (i), (ii) and (iii), we get 5

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