Show that.(i) (ii) (iii) (iv) (v)

(i) First Find the value of LHS

Using Identity (a + b) 2 = a2 + 2ab + b2 for finding the value of

In the given expression a =

On substituting these values in the above identity, we get

………………………………………………..(i)

On Adding in eqn (i), we get

First Find the value of RHS

Using Identity (a - b) 2 = a2 - 2ab + b2 for finding the value of

In the given expression a =

On substituting these values in the above identity, we get

………………………………………………..(i)

Therefore from eqn (i) and equ (ii) we found that LHS = RHS

(ii) First Find the value of LHS

Using Identity (a - b) 2 = a2 - 2ab + b2 for finding the value of

In the given expression a =

On substituting these values in the above identity, we get

………………………………………………..(i)

On Adding in eqn (i), we get

First Find the value of RHS

Using Identity (a + b)2 = a2 + 2ab + b2 for finding the value of

In the given expression a =

On substituting these values in the above identity, we get

………………………………………………..(ii)

Therefore from eqn (i) and equ (ii) we found that LHS = RHS

(iii) First Find the value of LHS

Using Identity (a - b) 2 = a2 - 2ab + b2 for finding the value of

In the given expression a =

On substituting these values in the above identity, we get

………………………………………………..(i)

On Adding in eqn (i), we get

Therefore we found that LHS = RHS

(iv) First Find the value of LHS

Using Identity (a + b) 2 = a2 + 2ab + b2 for finding the value of

In the given expression a =

On substituting these values in the above identity, we get

………………………………………………..(i)

Using Identity (a - b) 2 = a2 - 2ab + b2 for finding the value of

In the given expression a =

On substituting these values in the above identity, we get

………………………………………………..(ii)

On subtracting eqn (ii) from eqn (i), we get

Therefore we found that LHS = RHS

(v) Using Identity (a + b)(a - b) = a2 - b2

In the given expression a =

On substituting these values in the above identity, we get

……………………………………………………….(i)

On substituting these values in (b - c) (b + c), we get

……………………………………………………….(ii)

On substituting these values in (c - a) (c + a), we get

……………………………………………………….(iii)

On adding eqn (i), (ii) and (iii), we get

5