Evaluate the following integrals:

Expanding (cos x + sin x)2 = cos2x + sin2x + 2 sinx cosx


We know cos2x + sin2x = 1, 2sinxcosx = sin2x


(cos x + sin x)2 = 1 + sin2x


we can write the given equation as



Assume 1 + sin2x = t



2cos2x dx = dt


cos2xdx =


Substituting these values in the above equation we get



+ c


substituting t = 1 + 2 sin x in above equation



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