Evaluate the following integrals:

Assume x2 + sin2x + 2x =t


d(x2 + sin2x + 2x) =dt


(2x + 2cos2x + 2)dx = dt


2(x + cos2x + 1)dx = dt


(x + cos2x + 1)dx =


Put t and dt in given equation we get



=


But t = x2 + sin2x + 2x


=


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